I’d have just let the bat as usual.

Isn’t that three outs; innng over?

Edit - I read it again and understand you are suggesting what **would** score the run.

so a 5-4-3 double play could score the run from third. The out at home plate is not a given because the runner on third is not forced to run.

A better base runner might have avoided getting picked off, but the safety squeeze play isn’t the problem.

Besides, a squeeze is fun for the spectators.

And a faster runner at third.

Major leaguers are not taught to bunt . It goes against the stupidity of the three perfect outcomes (hr, walk, strikeout).

There are only a handful of competent bunters in the league. So. No.

Additionally, with a 26 man roster you should pinch run for the catcher.

As you were prefacing it, I thought you were looking for IBB to load bases to get force out at home.

"runners on first and third, no outs.

A sac fly from the #9 hitter scores the go-ahead run. "
Sac fly so 1 out, one on?


"An in-field double play scores the run."
How does this happen with one out, one on?
"Assuming" there is a scenario that this is even possible, a double play with 1 out ends the inning. Correct?

There were no outs with runners on first and third. If there was one out then yes, a double play ends the inning and the run doesn't score.

Though in over-thinking it, it's probably unlikely a double play would be attempted anyhow.

The SS or 2ND baseman would check the runner on third and go for the out at first or second, depending where the ball is hit and the infielder is positioned. Now there's one out and one runner still on third and one on second or first. The game is still tied. NOW, a double play ends the inning.

Odds were in Cleveland's favor to let Arias swing away. A safety squeeze with the catcher on third an 0 outs makes no sense. One could argue in favor of the surprise factor of the squeeze, and maybe that's what Vogt was thinking. Well, surprise -- it failed. Embarrassingly so.